Calculating Work Done by Friction in a Downhill Race: Conservation of Motion

AI Thread Summary
The discussion focuses on calculating the work done by friction for a boy in a wheelchair racing downhill. Given his mass of 48.7 kg, initial speed of 1.23 m/s, and final speed of 6.27 m/s, participants emphasize the need to correctly apply the conservation of energy principles. The work-energy equation is highlighted, specifically the relationship between initial and final energies and the work done by friction and outside forces. Participants clarify that the work done by gravity should be calculated using the correct height of 2.37 m, not the slope length. The conversation aims to assist in setting up the calculations for determining the work done by friction accurately.
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Homework Statement


boy in a wheelchair (total mass, 48.7 kg) wins a race with a skateboarder. He has a speed of 1.23 m/s at the crest of a slope 2.37 m high and 14.0 m long. At the bottom of the slope, his speed is 6.27 m/s. If air resistance and rolling resistance can be modeled as a constant frictional force of 41.8 N, calculate the work he did in pushing forward on his wheels during the downhill ride.


Homework Equations


Ei-Ef=Wfriction+Woutside forces

1/2mv^2, mgh

The Attempt at a Solution


cant seem to set this up right. don't know the equations for the 2 work
 
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Can't you think of a general expression for work that you could use here?
 
Not of the outside forces
 
that would be cool to get some help instead of pointing out that I am not smart, that's why I am asking for help
 
What are the outside forces?

In particular, what is the work done by gravity?
 
MgH=(48.7)(9.8)(14)
 
OK but H=2.37 m here, not 14m.

Now you just need to calculate the work done by friction.
 
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