Calculating Magnification of Christmas Tree Ornament

AI Thread Summary
The discussion focuses on calculating the magnification of a spherical Christmas tree ornament with a diameter of 4.76 cm, where an object is placed 11.9 cm away. The focal length is determined to be 1.19 cm using the formula f = 0.5 * r. The equation (1/di) + (1/do) = 1/f is applied to find the image distance (di), resulting in a value of approximately 1.32222 cm. The magnification (m) is calculated as -0.1111, indicating a reduced and inverted image. Participants question the type of mirror and its implications for the focal length, suggesting a need for clarification on the ornament's reflective properties.
Kris1120
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Homework Statement



A spherical Christmas tree ornament is
4.76 cm in diameter.
What is the magnification of the image of
an object placed 11.9 cm away from the ornament?

Homework Equations



f = .5* r

(1/di) + (1/do) = 1/f

m=-(di/do)

The Attempt at a Solution



f = .5*2.38 = 1.19 cm

(1/di) = (1/1.19) - (1/11.9) = 1.32222 cm

m =-(1.32222/11.9) = -0.1111
 
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Hi Kris1120,

Kris1120 said:

Homework Statement



A spherical Christmas tree ornament is
4.76 cm in diameter.
What is the magnification of the image of
an object placed 11.9 cm away from the ornament?

Homework Equations



f = .5* r

(1/di) + (1/do) = 1/f

m=-(di/do)

The Attempt at a Solution



f = .5*2.38 = 1.19 cm

I don't believe this is right. What type of mirror is this? What does that tell you about the focal length?
 

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