Cost of 41kW Motor for 32 Weeks: $17,633.28

[Onoff32]

Homework Statement

If I calculate that a motor needs 41kW continuously throughout a day to run, and it costs $0.08 per kWh to run, to calculate the cost of this for 32 weeks, I would do 41 x 24hours x 7days x 32weeks x $0.08 = $17633.28

is this a correct way of working it out?

 

[Mark44]

Homework Statement

If I calculate that a motor needs 41kW continuously throughout a day to run, and it costs $0.08 per kWh to run, to calculate the cost of this for 32 weeks, I would do 41 x 24hours x 7days x 32weeks x $0.08 = $17633.28

is this a correct way of working it out?

Your number is are correct, but your units don't make any sense.

Here's what you should have, including the appropriate units.
$41 kW \times 24 \frac{\text{hours}}{\text{day}} \times 7 \frac{\text{days}}{\text{week}} \times 32 \text{weeks} \times .08 \frac{}{\text{kWh}} = 17,633.28$.
The day units cancel, the week units cancel, and the kWh units cancel, so you're left with dollar units.
41 kW times 1 hour = 41 kWh, or 1 kW times 41 hours = 41 kWh, as well.

 

[CherryB]

Would that work for generation as well? If a generator puts out 1MegaWatt then it would follow that
1MW x 24 hours/day x 365 days/year=8,760 MWh or 8,760,000 kWH? Thank you

 

[OmCheeto]

Would that work for generation as well? If a generator puts out 1MegaWatt then it would follow that
1MW x 24 hours/day x 365 days/year=8,760 MWh or 8,760,000 kWH? Thank you

That's what I get, so I'll say the answer is yes.
Though a nit-picky person might say you forgot the "per year": 8,760,000 kWH per year