Couple Trig Problems

  • Thread starter Jacob87411
  • Start date
  • #1
171
1
A few trig problems that require the same thing or concept. As always I appreciate the help.

1) If Tan A=1/3 and Tan B=1/2 show that Tan(1/3 + 1/2) = 1

(Tan1/2 + Tan1/3) / 1-tan(1/2)tan(1/3)

I am a little confused with this because I cant use a calculator and am confused on what exactly to do here. I dont know Tan1/2 or Tan 1/3..I know it of pie/2 and pie/3 but its not the same?

2) Tan(7Pie/4 - 1/3)

Sort of the same thing, if I figure out what to do with the 1/3 i should be good. The 7Pie/4 = 315 = -1..so is it just Tangent of -4/3?

Thanks again for taking the time
 

Answers and Replies

  • #2
2,209
1
[tex]Tan(A+B) = \frac{\tan A + \tan B}{1-\tan(A)\tan(B)}[/tex]

You mistook Tan(A) = 1/2 for tan(1/2) = A

Use the above equation for #2 with [itex] A =\frac{7\pi}{4} \ and \ B = (-1/3)[/tex]
 
  • #3
91
0
Jacob87411 said:
A few trig problems that require the same thing or concept. As always I appreciate the help.

1) If Tan A=1/3 and Tan B=1/2 show that Tan(1/3 + 1/2) = 1

(Tan1/2 + Tan1/3) / 1-tan(1/2)tan(1/3)

I am a little confused with this because I cant use a calculator and am confused on what exactly to do here. I dont know Tan1/2 or Tan 1/3..I know it of pie/2 and pie/3 but its not the same?

2) Tan(7Pie/4 - 1/3)

Sort of the same thing, if I figure out what to do with the 1/3 i should be good. The 7Pie/4 = 315 = -1..so is it just Tangent of -4/3?

Thanks again for taking the time
1. Are you sure it's not [tex]Tan(a+b)[/tex].
2. Combine the fraction
* Edit sorry posted before i saw whozum's
 

Related Threads on Couple Trig Problems

  • Last Post
Replies
15
Views
2K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
1
Views
888
  • Last Post
Replies
9
Views
4K
Top