Cylinder gas, pressure question

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Homework Help Overview

The discussion revolves around a physics problem involving gas behavior in a cylinder, specifically focusing on how to calculate the new pressure after a piston is compressed. The context includes the ideal gas law and considerations of constant variables.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the ideal gas law (PV = nRT) and its application, questioning how to calculate the number of moles and whether to use alternative equations like p1v1/t1 = p2v2/t2. There are also inquiries about the correctness of specific pressure values and the implications of precision in measurements.

Discussion Status

The discussion is active, with participants exploring different methods and questioning assumptions about the problem setup. Some guidance has been offered regarding the use of the ideal gas law and the importance of precision in measurements, but no consensus has been reached on the final answer.

Contextual Notes

Participants note that the temperature remains constant and express confusion over the precision of pressure measurements, which influences their calculations.

yopy
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I know how to setup the entire problem i just don't know how to calculate the new pressure after the piston is compressed.
 
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yopy said:
I know how to setup the entire problem i just don't know how to calculate the new pressure after the piston is compressed.

PV = nRT

n, R, T remain the same. They give you everything else.
 
LowlyPion said:
PV = nRT

n, R, T remain the same. They give you everything else.

how do i calculate the number of moles?
 
maybe p1v1/t1 = p2v2/t2 is more appropriate?
 
RoryP said:
maybe p1v1/t1 = p2v2/t2 is more appropriate?

i don't think so, this is actually from my physics class and we never covered that
 
ok fair enough
just out of interest is the answer 234375 Pa?
 
What Rory is saying is that PV = nRT is the general equation but nRT and are constant
So p1v1 = p2v2, rearrange a little and you have the answer
 
RoryP said:
ok fair enough
just out of interest is the answer 234375 Pa?

not sure, has yet to be handed in
 
ahhh yes even more simple! forgot the temperature remained constant!
ok fair enough, would you be as kind enough to tell us the answer as i am revising for my physics A-level at the minute so all questions are useful!
 
  • #10
RoryP said:
just out of interest is the answer 234375 Pa?
No.

The volume goes from 0.750 -> 0.480 m^3, the pressure starts at 1.50 x10^5 Pa
so the final pressure is (0.750/0.480) * 1.50 x10^5 Pa = 2.34 x10^5 pa

You understand why your answer is wrong?
 
  • #11
mgb_phys said:
No.

The volume goes from 0.750 -> 0.480 m^3, the pressure starts at 1.50 x10^5 Pa
so the final pressure is (0.750/0.480) * 1.50 x10^5 Pa = 2.34 x10^5 pa

You understand why your answer is wrong?

lol that's the answer i got, except yours is in standard form! lol
 
  • #12
This is a 'physics' A level not maths
2.34 x10^5 is correct 234375.000000000000000000000 pa is wrong - whatever your calculator says!

Hint, what's the precision of the initial pressure measurment
 
  • #13
oooohhh slightly harsh!
but never the less that's fair enough!
no wonder my physics teacher is always annoyed with me for leaving whole answers!
 
  • #14
RoryP said:
maybe p1v1/t1 = p2v2/t2 is more appropriate?

yea this is the correct way to do it, thanks
 
  • #15
RoryP said:
ahhh yes even more simple! forgot the temperature remained constant!
ok fair enough, would you be as kind enough to tell us the answer as i am revising for my physics A-level at the minute so all questions are useful!

http://wug.physics.uiuc.edu/cc/IAState/Phys221/spring/homework/written%20homework/index.html


have at it.
 
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