Cylindrial Coordinates to evaluate the integral

In summary: Then I have ∫ ∫ ∫ z er2+z2 dz dr dθIn summary, The conversation is about finding the volume of a sphere in the first octant using integration. The integral to be used is ∫∫∫ ze^(x^2+y^2+z^2) with limits 0<= z<= √1-r2, 0 <= r <= 1, and 0<=θ<=π/2, in cylindrical coordinates.
  • #1
nysnacc
184
3

Homework Statement


upload_2016-9-27_22-24-29.png


Homework Equations


x^2+y^2 = r^2

The Attempt at a Solution


I think it is asking me to find the volume of the sphere, which is in the first octant (1/8 of the sphere)

So I set
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2
 
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  • #2
Hi, remember that if you want the volume of ##D## you must calculate ##\int\int\int_{D}1dxdydz## where ##f(x,y,z)=1## ...
 
  • #3
I think the question wants me to use the du dv
 
  • #4
nysnacc said:
I think it is asking me to find the volume of the sphere

no because ##f(x,y,z)\not=1## ...
 
  • #5
?
 
  • #6
What I want to say is that your coordinates are ok ## x=r\cos{\theta}, y=r\sin{\theta}, z=z ## but evaluating the integral you don't have the volume of the sphere (as you said ...) but simply a result that is the evaluation of the integral ...
 
  • #7
So simply put, do I just plug in the limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

and into the zex2+y2+z2

then the integral will be something like ∫∫∫∫ z dz r dr dθ
 
  • #8
nysnacc said:
So simply put, do I just plug in the limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

and into the zex2+y2+z2

then the integral will be something like ∫∫∫∫ z dz r dr dθ
Your integrand will be ##ze^{x^2+y^2+z^2}## in cylindrical coordinates with ##dV = r~dz~dr~d\theta##.
 
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  • #9
LCKurtz said:
Your integrand will be ##ze^{x^2+y^2+z^2}## in cylindrical coordinates with ##dV = r~dz~dr~d\theta##.

Okay but where does z goes (it was before ##e^{x^2+y^2+z^2}##)
 
  • #10
nysnacc said:
Okay but where does z goes (it was before ##e^{x^2+y^2+z^2}##)
?. Right where I have it.
 
  • #11
I rewrite my thought
Originally I have limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

Then I use them on ∫ ∫ ∫

replace also ex^2+y^2+z^2 with er2+z2

Then I have ∫ ∫ ∫ z er2+z2 r dz dr dθ
 

1. What are cylindrical coordinates?

Cylindrical coordinates are a type of coordinate system used to describe points in three-dimensional space. They are defined by a radial distance from the origin, an angle from a reference plane, and a height above or below the reference plane.

2. How do you convert from rectangular coordinates to cylindrical coordinates?

To convert from rectangular coordinates (x, y, z) to cylindrical coordinates (r, θ, z), you can use the following equations:
r = √(x^2 + y^2)
θ = tan^-1(y/x)
z = z

3. How do you evaluate an integral using cylindrical coordinates?

To evaluate an integral using cylindrical coordinates, you first need to convert the integral limits and the integrand from rectangular coordinates to cylindrical coordinates. Then, you can use the appropriate integration formulas for cylindrical coordinates, which are similar to those for polar coordinates.

4. What are the advantages of using cylindrical coordinates?

One advantage of using cylindrical coordinates is that they are well-suited for problems involving cylindrical or circular symmetry. They can also simplify certain types of integrals, making them easier to solve.

5. Can cylindrical coordinates be used to describe points in higher dimensions?

No, cylindrical coordinates are only applicable in three-dimensional space. In higher dimensions, other coordinate systems, such as spherical coordinates, may be used to describe points in space.

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