Cylindrial Coordinates to evaluate the integral

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Homework Help Overview

The discussion revolves around evaluating a triple integral in cylindrical coordinates, specifically related to finding the volume of a sphere in the first octant. The original poster attempts to set up the integral with appropriate limits for the variables involved.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the integral, questioning the correct form of the integrand and the limits of integration. There is mention of using cylindrical coordinates and the need to clarify the function being integrated.

Discussion Status

Some participants provide guidance on the structure of the integral and the use of cylindrical coordinates, while others express confusion about the integrand and its components. Multiple interpretations of the problem setup are being explored.

Contextual Notes

There are indications of uncertainty regarding the integrand and the limits of integration, as well as the specific function to be evaluated. The discussion reflects an ongoing exploration of these elements without reaching a definitive conclusion.

nysnacc
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Homework Statement


upload_2016-9-27_22-24-29.png


Homework Equations


x^2+y^2 = r^2

The Attempt at a Solution


I think it is asking me to find the volume of the sphere, which is in the first octant (1/8 of the sphere)

So I set
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2
 
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Hi, remember that if you want the volume of ##D## you must calculate ##\int\int\int_{D}1dxdydz## where ##f(x,y,z)=1## ...
 
I think the question wants me to use the du dv
 
nysnacc said:
I think it is asking me to find the volume of the sphere

no because ##f(x,y,z)\not=1## ...
 
?
 
What I want to say is that your coordinates are ok ## x=r\cos{\theta}, y=r\sin{\theta}, z=z ## but evaluating the integral you don't have the volume of the sphere (as you said ...) but simply a result that is the evaluation of the integral ...
 
So simply put, do I just plug in the limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

and into the zex2+y2+z2

then the integral will be something like ∫∫∫∫ z dz r dr dθ
 
nysnacc said:
So simply put, do I just plug in the limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

and into the zex2+y2+z2

then the integral will be something like ∫∫∫∫ z dz r dr dθ
Your integrand will be ##ze^{x^2+y^2+z^2}## in cylindrical coordinates with ##dV = r~dz~dr~d\theta##.
 
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LCKurtz said:
Your integrand will be ##ze^{x^2+y^2+z^2}## in cylindrical coordinates with ##dV = r~dz~dr~d\theta##.

Okay but where does z goes (it was before ##e^{x^2+y^2+z^2}##)
 
  • #10
nysnacc said:
Okay but where does z goes (it was before ##e^{x^2+y^2+z^2}##)
?. Right where I have it.
 
  • #11
I rewrite my thought
Originally I have limits:
0<= z<= √1-r2
0 <= r <= 1
0<=θ<=π/2

Then I use them on ∫ ∫ ∫

replace also ex^2+y^2+z^2 with er2+z2

Then I have ∫ ∫ ∫ z er2+z2 r dz dr dθ
 

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