D.E. + Integration: Find Value of k

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Homework Statement



Let [URL]http://203.196.176.41/VLEBT_RootRepository/Resources/b38e1b90-9ba0-45c6-a1eb-65288fa31b27.gif,[/URL] x > 0. If [URL]http://203.196.176.41/VLEBT_RootRepository/Resources/47280b1e-999e-44b0-a05e-5ad5243b0750.gif,[/URL] then one of the possible values of k is

1)16
2)63
3)64
4)15

The Attempt at a Solution



Do I have to integrate the first function to find out f(x)? I think that function is non-integrable.
 
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If you write the 2nd integral as: \int ^4 _1 \frac {3e^{sint^3}} {t} dt and then let x = t3, you will see the way :wink:
 
I got it. But then there is no use of the first sentence, right?
 
"Fundamental Theorem of Calculus"! That first part is telling you that, in the second part, you are integrating the derivative of f.
 
@Abdul Quadeer: Not sure what you meant :rolleyes:
 
Once you make the substitution u= x^3 as hikaru1221 suggested, you will be integrating (df/du)du. What is that integral?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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