Net magnetic field due to short barmagnets

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Homework Help Overview

The problem involves determining the net magnetic field at a point due to two short magnets with equal dipole moments, arranged perpendicularly. The point of interest is located on the bisector of the right angle formed by the magnets.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the effective dipole moment of the magnet configuration and its implications for calculating the magnetic field. There is confusion regarding the direction and magnitude of the magnetic field produced by each magnet, as well as the correct dependence on distance.

Discussion Status

Participants have offered various approaches to the problem, including the calculation of the resultant dipole moment and the magnetic field. Some have noted errors in previous expressions and emphasized the need for careful consideration of the assumptions underlying the approach used.

Contextual Notes

There are indications that the method discussed may not be universally applicable to other configurations of magnets, and participants are exploring the conditions under which the approach holds true.

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Homework Statement


Two short magnets of equal dipole moments M are fastened perpendicularly at their centres as shown. The magnetic field (magnitude) at a point P, distant d from the centre on the bisector of the right angle is ?

[URL]http://203.196.176.41/VLEBT_RootRepository/Resources/8f3a3668-e3a2-45c9-beae-68d195a290f4.gif[/URL]

The Attempt at a Solution



I am confused on finding out the magnitude of the net magnetic field.
The magnitude of the magnetic field due to each magnet (I don't know their direction) is μM/(4√2πd2)
 
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The combination of two short magnets a shown in the problem has an effective dipole moment equal to sqrt(2)*M along the bisector of the right angle.
 
That is a great approach!
So the resultant dipole moment is √2M and the resultant field is μ2√2M/4πd2
 
Abdul Quadeer said:
That is a great approach!
So the resultant dipole moment is √2M and the resultant field is μ2√2M/4πd2
No. For short magnet, the field is inversely proportional to d3
 
I copy-pasted the denominator from previous expression and forgot to change the square to cube. It should be μ2√2M/4πd3
 
The combination of two short magnets a shown in the problem has an effective dipole moment equal to sqrt(2)*M along the bisector of the right angle.

Note for Abdul: This approach is only correct for this problem. It's not true in general, not even in another problem with another pair of magnets of some different configurations.
 
hikaru1221 said:
not even in another problem with another pair of magnets of some different configurations.

Like?
 
2 magnets positioned at some distance from each other, provided that the point of interest P is not equidistant from the magnets and the medium is homogenous. You want to guess the reason? :wink:
 
May be this approach is fine only when the point lies on the line of resultant dipole moment?
 
  • #10
Nope. Think a bit hard: The essence of the approach is to combine 2 moments. If the approach is not applicable, the resultant moment should not "exist" or have some sort of meaning. Therefore, talking about the resultant moment (or "when the point lies on the line of resultant dipole moment" in particular) doesn't make much sense.

So that's a hint: it's not about the resultant moment. It should be about why the resultant moment should not "exist" here.

A further hint: B-field by M depends on M and the distance d from M to the point of interest P.

P.S.: M denotes vector M. I'm not sure what's wrong with LaTex :rolleyes:
 

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