\int_0^1 \sqrt{x} - x^3 dx How do I evaluate this? what does \sqrt{x} -x^3 = ?
May 5, 2009 #1 tweety1234 112 0 [itex] \int_0^1 \sqrt{x} - x^3 dx [/itex] How do I evaluate this? what does [itex] \sqrt{x} -x^3 = [/itex] ?
[itex] \int_0^1 \sqrt{x} - x^3 dx [/itex] How do I evaluate this? what does [itex] \sqrt{x} -x^3 = [/itex] ?
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May 5, 2009 #2 Cyosis Homework Helper 1,495 0 It is [tex]\sqrt{x}+(-x^3) \Rightarrow \int_0^1 \sqrt{x}+(-x^3) dx=\int_0^1 \sqrt{x}+\int_0^1 -x^3 dx[/tex]
It is [tex]\sqrt{x}+(-x^3) \Rightarrow \int_0^1 \sqrt{x}+(-x^3) dx=\int_0^1 \sqrt{x}+\int_0^1 -x^3 dx[/tex]
May 5, 2009 #3 HallsofIvy Science Advisor Homework Helper 41,833 961 [itex]\sqrt{x}- x^3= x^{1/2}- x^3[/itex]. That should be easy to integrate using the "power rule".