\int_0^1 \sqrt{x} - x^3 dx How do I evaluate this? what does \sqrt{x} -x^3 = ?
May 5, 2009 #1 tweety1234 112 0 [itex] \int_0^1 \sqrt{x} - x^3 dx [/itex] How do I evaluate this? what does [itex] \sqrt{x} -x^3 = [/itex] ?
[itex] \int_0^1 \sqrt{x} - x^3 dx [/itex] How do I evaluate this? what does [itex] \sqrt{x} -x^3 = [/itex] ?
Related Calculus and Beyond Homework Help News on Phys.org Flight of fancy? Aviation industry tries to go green Candy, cheese soar to space station to satisfy crew cravings Earth's cousins: Upcoming missions to look for 'biosignatures' in exoplanet atmospheres
Related Calculus and Beyond Homework Help News on Phys.org Flight of fancy? Aviation industry tries to go green Candy, cheese soar to space station to satisfy crew cravings Earth's cousins: Upcoming missions to look for 'biosignatures' in exoplanet atmospheres
May 5, 2009 #2 Cyosis Homework Helper 1,495 0 It is [tex]\sqrt{x}+(-x^3) \Rightarrow \int_0^1 \sqrt{x}+(-x^3) dx=\int_0^1 \sqrt{x}+\int_0^1 -x^3 dx[/tex]
It is [tex]\sqrt{x}+(-x^3) \Rightarrow \int_0^1 \sqrt{x}+(-x^3) dx=\int_0^1 \sqrt{x}+\int_0^1 -x^3 dx[/tex]
May 5, 2009 #3 HallsofIvy Science Advisor Homework Helper 41,791 919 [itex]\sqrt{x}- x^3= x^{1/2}- x^3[/itex]. That should be easy to integrate using the "power rule".