Definition of electric field dE due to a small charge dQ

AI Thread Summary
The equation dE = (kdQ/r^2)(cosθ i + sinθ j) represents the electric field due to a small charge dQ, derived from Coulomb's law. A small charge can be approximated as a point charge, simplifying the calculations. The unit vector in Cartesian coordinates, denoted as r̂, is used to express the direction of the electric field. Understanding the components of the equation, including the roles of sine and cosine, clarifies its application. This foundational knowledge is essential for solving related physics problems effectively.
twotaileddemon
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Homework Statement



Hi...
How can one be sure that
<br /> d\textbf{E}=\frac{kdQ}{r^2}(\cos\theta \textbf{i} + \sin\theta \textbf{j})<br />
Is true for a small charge dQ
Is there some derivation for this?

Homework Equations

The Attempt at a Solution



I have a problem for homework that uses this equation... I know how to solve the problem, but I feel like I should know how this equation works since I don't want to just mindlessly plug in information... Thanks.
 
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A small enough charge dQ can be considered a point charge. The equation is just a statement of Coulomb's law.

<br /> d\textbf{E}=\frac{kdQ}{r^2}\hat{r}<br />

The unit vector \hat{r} in Cartesian coordinates gives you what you have.
 
naresh said:
A small enough charge dQ can be considered a point charge. The equation is just a statement of Coulomb's law.

<br /> d\textbf{E}=\frac{kdQ}{r^2}\hat{r}<br />

The unit vector \hat{r} in Cartesian coordinates gives you what you have.

Ohh okay I get it now, thanks. I understand where the sin and cosine come from now
:)
Thanks so much!
 
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