- #1
MathematicalPhysicist
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- I want to show the identity:
##\partial^2_t \int T^{00}(x^i x_i)^2 d^3x = 4\int T^i_i x^j x_j d^3x + 8\int T^{ij}x_i x_j d^3x##
by using the identity: ##T^{\mu \nu}_{,\nu}=0##, for a bounded system (i.e. a system for which ##T^{\mu \nu}=0## outside a bounded region of space).
I'll write down my calculations, and I would like if someone can point me to my mistakes.
$$\partial_t \int T^{00}(x^i x_i)^2 d^3 x = -\int T^{0k}_{,k}(x^i x_i)^2 d^3 x = \Dcancelto[0]{-\int (T^{0k}(x_ix^i)^2)_{,k}d^3 x} +\int (T^{0k}(x_i x^i)^2_{,k})d^3 x$$
After that:
$$\partial_t \int T^{0k} [ 2x_k (x^k)^2+2(x_k)^2 x^k] d^3 x = \int T^{0k},0 [ 2x_k (x^k)^2+2(x_k)^2 x^k] d^3 x = $$
$$=-\int T^{kj}_{,j}[2x_k(x^k)^2+2(x_k)^2 x^k] =\[ \Dcancelto[0]{-\int (T^{kj}[ 2x_k(x^k)^2+2(x_k)^2x^k])_{,j}d^3 x}\] + \int T^{kj}[2\delta_{jk}(x^k)^2+4x_k x^k \delta^k_j + 2(x_k)^2\delta^k_j+4x_k \delta_{jk} x^k ] d^3 x$$
How to continue? assuming my above work is correct?
Thanks!
The \Dcancelto should be the arrow that goes to zero, I am not sure how to fix this here.
$$\partial_t \int T^{00}(x^i x_i)^2 d^3 x = -\int T^{0k}_{,k}(x^i x_i)^2 d^3 x = \Dcancelto[0]{-\int (T^{0k}(x_ix^i)^2)_{,k}d^3 x} +\int (T^{0k}(x_i x^i)^2_{,k})d^3 x$$
After that:
$$\partial_t \int T^{0k} [ 2x_k (x^k)^2+2(x_k)^2 x^k] d^3 x = \int T^{0k},0 [ 2x_k (x^k)^2+2(x_k)^2 x^k] d^3 x = $$
$$=-\int T^{kj}_{,j}[2x_k(x^k)^2+2(x_k)^2 x^k] =\[ \Dcancelto[0]{-\int (T^{kj}[ 2x_k(x^k)^2+2(x_k)^2x^k])_{,j}d^3 x}\] + \int T^{kj}[2\delta_{jk}(x^k)^2+4x_k x^k \delta^k_j + 2(x_k)^2\delta^k_j+4x_k \delta_{jk} x^k ] d^3 x$$
How to continue? assuming my above work is correct?
Thanks!
The \Dcancelto should be the arrow that goes to zero, I am not sure how to fix this here.