Derive the expression for isothermal change in Constant Volume Heat Capacity

AI Thread Summary
The discussion focuses on deriving the expression for the isothermal change in Constant Volume Heat Capacity, specifically (dCv/dV)T = T(d2P/dT2)V. The initial attempt involves using the ideal gas law, P=nRT/V, leading to the first derivative (dP/dT) = R/V. However, the contributor mistakenly concludes that the second derivative (d2P/dT2) equals zero, resulting in (dCv/dV) being zero. This indicates a misunderstanding of the derivatives involved in the context of heat capacity changes. Clarification and further assistance are sought to correctly derive the expression.
eagerbeaver92
Messages
3
Reaction score
0

Homework Statement


Derive the following expression for calculating the isothermal change in Constant Volume Heat Capacity:

(dCv/dV)T = T(d2P/dT2)V


Homework Equations





The Attempt at a Solution



I have no idea, please help
 
Physics news on Phys.org
How about this?

assuming ideal gas:

P=nrt/V

then

(dP/dT) = R/V , ignoring moles

and

(d2P/d2T) = 0

so (dCv/dV)=T*0=0
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top