Design 1.5 A Solenoid & Charge 1.5 V Battery

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Discussion Overview

The discussion revolves around designing a solenoid capable of generating a minimum of 1.5 A of current to charge a 1.5 V battery. Participants explore the necessary parameters such as the number of turns and length of the solenoid, as well as the relationship between the solenoid's design and its efficiency in generating the desired current.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes their initial design of a solenoid, noting it is approximately 10 cm in length with an estimated 2-3 thousand turns, generating about 50 V PK-PK AC.
  • Another participant requests clarification on the original post, suggesting that a clearer description or a diagram would help in understanding the project.
  • Some participants propose that the project resembles a homemade transformer and rectifier setup for charging a battery from mains electricity.
  • There is a suggestion that the solenoid functions as a dynamo, with a moving magnet relative to the coil, and that the speed of movement affects the frequency of the generated AC output.
  • One participant mentions the need for a rectifier to convert AC to DC for charging the battery and speculates that higher frequency AC may lead to higher DC output, though they express uncertainty about the math involved.
  • The original poster seeks guidance on how to determine the number of turns and length required to achieve the desired current of 1.5 A.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the original post, with some seeking clarification and others proposing different interpretations of the project. There is no consensus on the specific design parameters or calculations needed to achieve the desired current.

Contextual Notes

Participants have not provided specific theoretical calculations or established formulas for determining the necessary turns and lengths of the solenoid based on the desired current. The discussion reflects a range of assumptions and interpretations regarding the solenoid's operation and design.

p0uya
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Hey All,
I'm trying to design a solenoid that would generate about minimum 1.6 A of current in order for me to charge up a 1.5 A 1.5 V battery. I already designed one which is about 10CM in length and unknown number of turns (as I used a drill to wind the coils around it. so I would guess its about 2-3 thousands turns).
I'm getting about 50 V PK-PK AC . However, I was hoping to make my solenoid smaller and more efficient. I did not perform any theoretical calculation on my first trial (mainly experimental)

I was hoping if someone could guide me in the right direction on how I could be able to achieve this much of current.
Is there a way to know how many turns/lengths I need based on only the current that I would like to have? B=Mni/l
If so, then how would I be able to guess the magnetic flux in the above equation?

Thank you all for taking the time reading my post.

Looking forward to your suggestions.Cheers.
 
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I can't make sense of your description. Perhaps you could better state what you are trying to do, and also draw a picture.
 
I need to design a solenoid which I could get about 1.5 A of current. I need to determine the number of turns and lengths of the solenoid. I hope That describes it better,
anorlunda said:
I can't make sense of your description. Perhaps you could better state what you are trying to do, and also draw a picture.
 
Are you trying to make a home made transformer + rectifier, so that you can charge a rechargeable battery from the mains electricity supply?
 
rootone said:
Are you trying to make a home made transformer + rectifier, so that you can charge a rechargeable battery from the mains electricity supply?
Im trying to charge a double A battery using a solenoid and magnet.
 
OK, got it now.
You are making a home made dynamo of sorts.
Your magnet is presumably arranged so that it's constantly moving in relation to the coil. (or the other way around).
Usually this is done by having one element or the other spinning.
One consideration is that the faster the spin the more higher frequency will be the ac output from the device.
You will need a rectifier component of course to convert your generated AC to DC so that the battery is charged.
I think but am not 100% certain, that the higher frequency AC (faster spinning) of the generator should result in a higher DC power output from the rectifier.
I'll leave the precise math to somebody else.
 
rootone said:
OK, got it now.
You are making a home made dynamo of sorts.
Your magnet is presumably arranged so that it's constantly moving in relation to the coil. (or the other way around).
Usually this is done by having one element or the other spinning.
One consideration is that the faster the spin the more higher frequency will be the ac output from the device.
You will need a rectifier component of course to convert your generated AC to DC so that the battery is charged.
I think but am not 100% certain, that the higher frequency AC (faster spinning) of the generator should result in a higher DC power output from the rectifier.
I'll leave the precise math to somebody else.
Thank you for your reply. The power is generated as the magnets moved horizontally in the solenoid as the person shakes the solenoid. This produces the AC voltage and then gets rectified to DC . My question was that how would I be able to exactly know how much turns or lengths do i require to produce 1.5 A of current.
 

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