Determination of the final temperature inside a calorimeter

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To solve the problem involving the heat exchange between a piece of copper and water in a calorimeter, the key principle is that the heat lost by the copper equals the heat gained by the water. The equation (T2-T1)*Cp*m = Q is crucial for calculating the final temperature. The specific heat capacities for copper and water are provided, along with their respective masses and initial temperatures. Once the final temperature is determined, the entropy changes for both the copper and the water can be calculated using the formula for entropy change, which involves the heat exchanged and the temperature. The total entropy change in the system is the sum of the individual entropy changes for the copper and water. The discussion highlights the importance of understanding heat transfer and thermodynamic principles to arrive at the solution.
soaring206
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Okay, I'm working on some pchem problems and I'm stuck on this one question...

A 5.33g piece of Cu metal is heated to 372.85K in boiling water, then dropped into a calorimeter containing 99.53g of water at 295.75K. The calorimeter is sealed to the outside environment, and the temperature equalizes. Cp[Cu(s)]=0.385 J/g*K, Cp[water]=4.184 J/g*K. What is the final temperature inside the system? What is the entropy change of the Cu metal? What is the entropy change of the liquid water? What is the total entropy change in the system?

I have absolutely no idea how to find the final temp of the system. Once I have that temp, I think I can figure out the entropy changes, but if someone could point me in the right direction for finding the final temperature, that would be great. Thank you in advance!
 
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Hint: (T2-T1)*Cp*m = Q. The heat lost by the Cu must equal the heat gained by the H2O.
 
Thanks, that helped a lot...I think I've figured it out now! :smile:
 
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