Determine equation of state from entropy

AI Thread Summary
The discussion focuses on deriving the equation of state from the given entropy expression S=a(VNU)^(1/3). An initial attempt involved expressing dS in terms of dP and dT, but this approach did not yield results. The use of Maxwell relations was also explored, specifically the relation between partial derivatives of S and P. A suggestion was made to utilize the definition of temperature, leading to the equation 1/T = (∂S/∂U) = (a/3)(VT/U^2)^(1/3). The conversation emphasizes the challenges in finding a clear path to the equation of state from the entropy function.
A_B
Messages
87
Reaction score
1

Homework Statement


The entropy is given as
S=a \left(VNU \right)^{\frac{1}{3}}
Find the equation of state.

2. The attempt at a solution
I've tried writing dS in terms of dP and dT then using the fact that dS is a perfect differential equate the partial derivatives of the terms. This got me nowhere. I also tried using Maxwell relations.
\left( \frac{\partial S}{\partial V} \right) _T = \left( \frac{\partial P}{\partial T} \right) _V

Thanks
Alex
 
Physics news on Phys.org
How about I use the definition of temperature?
\frac{1}{T} = \left( \frac{\partial S}{\partial U} \right) = \frac{a}{3} \left( \frac{VT}{U^2} \right)^{1/3}
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top