Determine the magnitude of the total force exerted by the track on the

AI Thread Summary
The discussion revolves around understanding the normal force in a free body diagram (FBD) related to a particle's motion. There is confusion regarding the direction of the normal force, with one participant asserting it should be upwards while the FBD shows it downwards. The resolution indicates that the direction of the normal force can vary based on conditions like speed and radius, and that a negative result from calculations simply indicates a misdirection in the chosen normal force. Ultimately, the magnitude of the forces is what matters for further calculations, particularly regarding friction. Clarifying the normal force's direction is essential for accurate problem-solving in physics.
TheDudeTR
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Homework Statement
i did not understand free body diagram in this question
Relevant Equations
F = ma
This is the question.
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This is the FBD in the solution given. What i didn't understand is the sense of normal force. in the question mg force pulls particle down and according to my logic normal vector should be upwards in this conditions. but it is downwards in the given FBD. when i try to solve question with my own way result is different because of in the question it takes normal axis equations as (N+mg.cos30=m*a) and i took it as (-N+mg.cos30=m*a ) where am i wrong? can you help me please.
 
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TheDudeTR said:
the sense of normal force
In principle it could be either way - depends on the speed and the radius, etc.
But you do not need to care which way it is when drawing the diagram. If you chose wrongly it will come out negative, but the frictional force only cares about the magnitude.
 
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