- #1
JasonZ
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Hey, this is from "Foundations of Electromagnetic Theory" by Reitz, et al. Problem 2-15.
I have had a really hard time trying to learn from this book as there are no examples to apply the equations they prove throughout the chapters. Anyhow, I don't really have anything down for this problem, which is as follows:
A spherical charge distribution has a volume charge density that is a function only of r, the distance from the center of the distribution. In other words, [tex] \rho = \rho (r)[/tex]. If [tex] \rho (r)[/tex] is as given below, determine the electric field as a function of r. Integrate the result to obtain an expression for the electrostatic potential [tex] \phi (r)[/tex], subject to the restriction that [tex] \phi (\infty) = 0[/tex].
(a) [tex] \rho = \frac {A}{r} [/tex] with A a constant for [tex] 0 \leq r \leq R; \rho = 0 [/tex] for [tex] r > R [/tex].
I assume this is a Guass law problem, I just don't understand how to solve the right hand integral, supposing it is indeed: [tex] \int \rho dv [/tex]
Can anyone help me, I am quite stuck.
-Jason
I have had a really hard time trying to learn from this book as there are no examples to apply the equations they prove throughout the chapters. Anyhow, I don't really have anything down for this problem, which is as follows:
A spherical charge distribution has a volume charge density that is a function only of r, the distance from the center of the distribution. In other words, [tex] \rho = \rho (r)[/tex]. If [tex] \rho (r)[/tex] is as given below, determine the electric field as a function of r. Integrate the result to obtain an expression for the electrostatic potential [tex] \phi (r)[/tex], subject to the restriction that [tex] \phi (\infty) = 0[/tex].
(a) [tex] \rho = \frac {A}{r} [/tex] with A a constant for [tex] 0 \leq r \leq R; \rho = 0 [/tex] for [tex] r > R [/tex].
I assume this is a Guass law problem, I just don't understand how to solve the right hand integral, supposing it is indeed: [tex] \int \rho dv [/tex]
Can anyone help me, I am quite stuck.
-Jason
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