1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Determining nuclear radius by electron diffraction

  1. Feb 28, 2007 #1
    can anyone explain to me, where does the equation [tex]R=\frac{0.61\lambda}{sin\theta}[/tex] come from when determining the approximate radius of the nucleus by electron scattering?
  2. jcsd
  3. Mar 1, 2007 #2
    I think it has something to do with diffraction. Look up "diffraction by a disk".
    I just read that it is possible to calculate the diffraction pattern behind a disc by Babinet's principle.
  4. Mar 1, 2007 #3
    sin(theta) = 1.22*lamda/D, from circular diffraction. D=2R, so R = 0.61*lamda/sin(theta).
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Determining nuclear radius by electron diffraction
  1. Electron diffraction (Replies: 1)