Determining nuclear radius by electron diffraction

  • Thread starter dt19
  • Start date
  • #1
47
0
can anyone explain to me, where does the equation [tex]R=\frac{0.61\lambda}{sin\theta}[/tex] come from when determining the approximate radius of the nucleus by electron scattering?
 

Answers and Replies

  • #2
705
15
I think it has something to do with diffraction. Look up "diffraction by a disk".
I just read that it is possible to calculate the diffraction pattern behind a disc by Babinet's principle.
 
  • #3
400
1
sin(theta) = 1.22*lamda/D, from circular diffraction. D=2R, so R = 0.61*lamda/sin(theta).
 

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