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Determining nuclear radius by electron diffraction

  1. Feb 28, 2007 #1
    can anyone explain to me, where does the equation [tex]R=\frac{0.61\lambda}{sin\theta}[/tex] come from when determining the approximate radius of the nucleus by electron scattering?
     
  2. jcsd
  3. Mar 1, 2007 #2
    I think it has something to do with diffraction. Look up "diffraction by a disk".
    I just read that it is possible to calculate the diffraction pattern behind a disc by Babinet's principle.
     
  4. Mar 1, 2007 #3
    sin(theta) = 1.22*lamda/D, from circular diffraction. D=2R, so R = 0.61*lamda/sin(theta).
     
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