- #1
faust9
- 692
- 2
Ok, I was given: Solve the following using superposition:
[tex]\ddot{x}+2\dot{x}+4x=\delta(t)[/tex]
bounded by [tex]\dot{x}=0, x(0)=0[/tex]
I solved the Homo eqn and got the following:
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))[/tex]
I also know that :
[tex]\ddot{x}+2\dot{x}+4x=u(t)[/tex]
equals
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))+\frac{1}{4}[/tex] from a previous problem.
So, I said:
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))+\frac{\delta (t)}{4}[/tex]
Is this correct thus far (the superposition part at least I'm pretty sure the diff eq portion is correct).
How do I deal with the delta function? Any help would be much appreciated!
[tex]\ddot{x}+2\dot{x}+4x=\delta(t)[/tex]
bounded by [tex]\dot{x}=0, x(0)=0[/tex]
I solved the Homo eqn and got the following:
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))[/tex]
I also know that :
[tex]\ddot{x}+2\dot{x}+4x=u(t)[/tex]
equals
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))+\frac{1}{4}[/tex] from a previous problem.
So, I said:
[tex]x(t)=e^{-t}(\cos (\sqrt{3}t)+\frac{\sqrt{3}}{3}\sin ({\sqrt{3}t))+\frac{\delta (t)}{4}[/tex]
Is this correct thus far (the superposition part at least I'm pretty sure the diff eq portion is correct).
How do I deal with the delta function? Any help would be much appreciated!
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