Difference between electric field intensity of plane and conducting sheet

AI Thread Summary
The discussion focuses on the differences in electric field intensity between an infinite plane charged sheet and an infinite conducting charged sheet. The electric field for the charged sheet is given by E = σ/2ε₀, while for the conducting sheet, it is E = σ/ε₀. The key distinction is that the electric field exists on both sides of the infinite plane charged sheet, whereas it only exists on one side of the conducting sheet. Participants also discuss deriving the formula for the conducting sheet using Gauss's law and the charge distribution pattern. The conversation concludes with one participant expressing gratitude for the clarification received.
Sumedh
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what is the difference between the electric field intensity of
1)infinite plane charged sheet whose formula is
E=\sigma/2\epsilono
and 2)infinite conducting charged sheet whose formula is
E = \sigma/\epsilono
 
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Sumedh said:
what is the difference between the electric field intensity of
1)infinite plane charged sheet whose formula is
E=\sigma/2\epsilono
and 2)infinite conducting charged sheet whose formula is
E = \sigma/\epsilono

Look at the top and bottom figure here:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/gausur.html#c3

One is a sheet of charge where the E field is on top and bottom. The other is where the E field is only on one side.

Zz.
 
How can we derive the formula for
'2)infinite conducting charged sheet whose formula is
E = σ/ϵo'
i am not cleared about the second point.
what will be the pattern of charge distribution on the conductor
and how it can be derived through direct integration?
 
Are you not familiar with Gauss's law?

Zz.
 
I am learning gauss law and is not perfect in it
 
Thank you very much for your valuable reply. I have got my answer after some trial and error. thank you very much.:smile:
 
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