Diffraction Grating - all visible light?

AI Thread Summary
To determine the smallest grating spacing for observing the entire visible spectrum (400nm to 700nm), the equation nλ = d sin θ is essential. The maximum wavelength for first-order diffraction is 700nm, and for second-order, it is 1400nm. The discussion raises questions about how to calculate the maximum angle for observing these wavelengths. Clarification on how to apply the grating equation effectively is needed. Understanding these principles will help in solving the problem accurately.
clamatoman
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Homework Statement


Find the smallest grating spacing that let's you see the entire visible spectrum.
400nm to 700nm comprises the visible light spectrum.
no other information is given.

Homework Equations


nλ=d sin θ

The Attempt at a Solution


I am not sure how to start as all i have been given is a spectrum of wavelengths...?
 
Physics news on Phys.org
Well, apparently its 700nm. And 1400 nm for the second order.
 
What is the maximum angle where a wavelength can be observed?
 

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