Direction of work of block colliding with spring

AI Thread Summary
The discussion centers on the nature of work in the context of a block colliding with a spring. It raises the question of whether the work vector is defined by force (F) or displacement (X), emphasizing that work is typically considered a scalar quantity derived from the multiplication of force and distance. The conversation highlights that work done along a path perpendicular to the force is zero, particularly in frictionless scenarios. Additionally, there is a note on the variability in textbooks regarding the sign convention for work done on a system, with some considering it negative and others positive. Overall, the topic explores fundamental concepts of work in physics and its representation in different educational resources.
zhenyazh
Messages
55
Reaction score
0
a general question.
suppose i have a spring and a block colliding it.
the direction of the work vector is it defined by F or by X.
 
Physics news on Phys.org


I never thought of work as a vector. As far as I can remember it is the scalar multiplication of force and distance. The fact that the work done on a path normal to the direction of force is zero (think about a frictionless surface and an object already moving along the surface) supports what I remember.
 


Work done on or by a system

It depend on which reference your book choice

some books take the work done on a system as negative and in other books positive
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top