Do Plate Materials Affect Capacitor Performance?

AI Thread Summary
The discussion centers on whether the material of capacitor plates affects capacitance, particularly at high frequencies. It concludes that the conductive material does not impact capacitance as long as equipotential conditions are maintained and the material behaves well in the presence of the electric field. At low frequencies, charges can reach equilibrium, leading to stable capacitance, while at high frequencies, charges may not keep up, disrupting this equilibrium. The conversation also touches on the role of conductivity, noting that it matters primarily when current flows, not in static capacitance scenarios. Overall, the material's impact on capacitance is limited under specific conditions, with calculations suggesting minimal differences at lower frequencies.
Aladdin123
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Hi
I was wondering about an issue i thought about while attending a masters thesis dissertation earlier

does the material of the plate (not the filling dielectric) affect capacitance (even if in the fringing level) ?
Check the attached picture , for a better explanation
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The conductive material will not effect capacitance so long as:

1 - Each conductor enforces an equipotential condition across its surface.

2 - The conductive material is well behaved in the presense of the required E-field.

A violation of (1) would be a capacitor with 1 square foot plate used for 1GHz signal.

A violation of (2) would be very high surface charge density, say from combination of high voltage and sharp edge on conductor, causing corona discharge.
 
But isn't aluminum a "better conductor" ?
isnt having a higher conductivity something that will upset the electric field distribution, since more charges will accumulate on the metal than on the silicon ?
 
"Better conductor" only matters if current is flowing through the conductor.

Capacitance is an electrostatic quantity. Charges are not in motion; they have arrived at their equilibrium positions which, in turn, creates the E field distribution that leads to the measured voltage between plates.

If your frequency is low enough that the charges are able to be, at any frozen moment in time, close to their electrostatic equilibrium positions, then the capacitance will be correspondingly close to the electrostatic capacitance ("quasi-static" approximation).

If your frequency is high enough that the charges are not able to keep up and reach their electrostatic equilibrium positions, then you no longer have equipotential surfaces.

Perhaps what you are saying is that we can extend the quasi-static approximation to higher frequencies in a given geometry if we use better conductors. This is true, but only to a certain extent. Part of the issue is finite propagation velocity. If I had a parallel plate capacitor made with superconducting plates 1 square foot in area, I would not expect to have equipotential surfaces at 1GHz.

Check out the free field solvers available at: http://www.fastfieldsolvers.com. or http://www.rle.mit.edu/cpg/research_codes.htm.
 
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So for micrometer level dimensions , running at the KHz speed :
The only issue I will see is a "series" resistance with the silicon part that is about 0.5 ohms ( Aluminum has resistivity 28.2 nΩ·m, while silicon 1KΩ·m) more than that of the aluminum part which will mean each part will behave as a low pass filter , with cutoff frequencies in the THz (RC=0.5*C , and Cap is ~ 10^-11 ) , so ... no difference at running in the KHz
BTW my calculations are just rough estimates

Am I right ?
 
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