Does Mixing Fluids A and B Create a Predictable Thermal Capacity?

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The discussion centers on the thermal capacity of a mixture created from two fluids, A and B, with respective thermal capacities C_a and C_b. The proposed formula for the new thermal capacity of the mixture, C_new, is C_new = C_a*X + C_b*(1-X), where X represents the percentage of fluid A in the mixture. It is clarified that this relationship holds true only if the fluids form an "ideal solution." An ideal solution is characterized by similar molecular attractions between the components, meaning the interactions between A and A, B and B, and A and B are nearly identical. If these conditions are not met, the thermal capacity may vary and should be evaluated on a case-by-case basis.
pomekrank
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Hi,
Say we have fluid A with thermal capacity C_a and fluid B with C_b. If we create a solution with X% of fluid A and (1-X)% of fluid B, is it true that the new thermal capacity of the mixture will be
C_new ?= C_a*X + C_b * (1-X)
Or it is a case-by-case relationship that depends on the nature of the fluids ?

Thank you
 
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Case by case.
 
pomekrank said:
Hi,
Say we have fluid A with thermal capacity C_a and fluid B with C_b. If we create a solution with X% of fluid A and (1-X)% of fluid B, is it true that the new thermal capacity of the mixture will be
C_new ?= C_a*X + C_b * (1-X)
Or it is a case-by-case relationship that depends on the nature of the fluids ?

Thank you
If A and B form a so-called "ideal solution," then your mixing rule is correct. For a solution to be ideal, the molecular attractions between A and A, B and B, and A and B must be nearly the same.
 
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