Does Ohm's Law still apply when the total number of Amps is limited?

AI Thread Summary
Ohm's Law, expressed as I = V/R, remains applicable even when the total number of amps is limited. However, if there are insufficient charge carriers, the current may not sustain itself at high voltage levels. The discussion highlights that a depletion of charge carriers will lead to a gradual decline in current rather than an immediate drop to zero. This interplay between voltage, resistance, and charge availability clarifies the conditions under which Ohm's Law holds true. Ultimately, the availability of charge carriers is crucial for maintaining high voltage and current levels.
Simfish
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As in, what if you have a VERY high voltage? Then I = V/R.

But what if you only have a limited number of charge carriers that could eventually run out? Then what will happen to the current? Will it suddenly stop following Ohm's Law? Will it immediately drop off to 0, or gradually drop off to 0?
 
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You can't have high voltage without enough charge being separated, so when you run out of charge carriers, you run out of high voltage as well.
 
Oh okay. That resolves the conundrum!
 
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