Doppler Effect of a blown whistle

AI Thread Summary
The problem involves a whistle with a frequency of 500 Hz rotating in a horizontal circle at 400 revolutions per minute. To find the frequencies heard by a listener, the Doppler effect must be applied, considering the whistle's motion towards and away from the observer. The radius of the circle is determined by the length of the string, which is 1.2 m. The conversion of revolutions per minute to revolutions per second is necessary to calculate the velocity of the whistle. Ultimately, the discussion focuses on determining the frequency range heard by the listener based on these calculations.
lha08
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Homework Statement


A whistle of frequency 500 Hz tied to the end of a string of length 1.2 m revolves at 400 rev/min. A listener standing some distance away in the plane of rotation hears frequencies in the range ____?
(speed of sound=340 m/s)
a) 436 to 586
b) 426 to 574
c) 426 to 584
d) 436 to 674


Homework Equations





The Attempt at a Solution


I'm not really sure how to approach this particular problem...i'm lost especially for the units and what to do with the string...thanks
 
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when the whistle is moving in a horizontal circle, at two points on the circle the whistle is moving either towards the observer or away from him. Apply Doppler effect to find the frequencies.
 
rl.bhat said:
when the whistle is moving in a horizontal circle, at two points on the circle the whistle is moving either towards the observer or away from him. Apply Doppler effect to find the frequencies.

okay i understand that part, but how do i convert 400 rev/min and for the length of the string do i use C=2(pi)radius and solve for r?
 
Last edited:
Velocity v = 2*pi*n*r where n is the number revolution per second.
 
rl.bhat said:
Velocity v = 2*pi*n*r where n is the number revolution per second.

but how do i solve for the radius using the length of the string?
 
lha08 said:
but how do i solve for the radius using the length of the string?
Length of the string itself is the radius.
 
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