Calculating Frequency Shift in the Doppler Effect for Submarine Sonar Waves

AI Thread Summary
The discussion revolves around calculating the frequency of sonar waves detected by Submarine B as it approaches Submarine A. The correct formula to use is frequency_observer = frequency_source * (v + v_D) / (v - v_S), where v is the speed of sound in water (1522 m/s), v_D is the speed of Sub B (18 m/s), and v_S is the speed of Sub A (4 m/s). After applying the correct values, the calculated frequency is approximately 1024.6 Hz, which rounds to 1024 Hz. The initial calculation of 1019 Hz was incorrect due to misapplication of the formula. Accurate input and rounding are crucial for obtaining the correct answer in such problems.
BoogieL80
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I'm working on the following problem:

Two submarines are underwater and approaching each other head-on. Sub A has a speed of 4 m/s and sub B has a speed of 18 m/s. Sub A sends out a 1010 Hz sonar wave that travels at a speed of 1522 m/s.

The question asks two questions, but I'm stuck on the first one:

What is the frequency of the sound detected by sub B (to the nearest Hz)?

I was using the formula frequencyobserver = frequencysource * 1 + (vobserver / velocity of sound) / 1 - (vsource / velocity of sound). I assumed that the numerator would use the positive sign since the observer is moving towards the source. I used the minus sign in the denominator since the source is moving towards the observer. For the speed of sound I used 1522 m/s since the submarines are traveling in salt water. I then multiply my calculated numbers times 1010 and got a frequncy of 1019 Hz. However webassign is telling me this is incorrect. Any help with what I'm doing wrong?
 
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Maybe you pluged in wrong data. Your equation looks correct to me.

f' = f \frac{v+v_D}{v-v_S}

where
v= 1522 m/s

v_D = 18 m/s

v_S = 4m/s

And my answer is f'=1024.6 Hz
 
My goodness, that thing was too picky. I put in 1023 Hz the first time and it didn't accept the number. Thank you for your help.
 
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