- #1
bombz
- 10
- 0
Homework Statement
Okay here's the problem:
Consider the region R interior to a circle(of r =2) and exterior to a circle(r=1).
1.Using cartesian coords and double integral, calc the area of annulus.
2. repeat calculation above but using double integral with polar coords
The Attempt at a Solution
So for 1, did I set it up right?
4 * (double integral, both bounds from 0 to 2) of [tex]\sqrt{(4-x^2)}[/tex] dydx - 4 * (double integral, both bounds from 0 to 1) of [tex]\sqrt{1-x^2}[/tex]
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2.
and this is 2, did i set it up right?
First bound is the outer integral, the one for dtheta
(double integral)(first bound 0 to 2 * PI)(Second: -2 to 2) of r dr dtheta - (double integral)(first bound 0 to 2 *PI)(second: -1 to 1) of r dr dtheta
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How do I solve these any further? I completely forgot. Thanks!