- #1
r_swayze
- 66
- 0
Use polar coordinates to find the volume of the given solid inside the sphere x^2 +y^2 + z^2 = 16 and outside the cylinder x^2 +y^2 = 4
I know how to set up the the integral to find the volume inside the sphere but I am not quite sure how to also find the outside of the cylinder. Can someone confirm if this right or wrong?
x^2 + y^2 +z^2 = 16
z^2 = 16 - x^2 - y^2
z = sqrt( 16 - r^2 )
since the problem asks for volume of the sphere z = 2*sqrt( 16 - r^2 )
x^2 + y^2 = 4
r^2 = 4
r = 2
so 2 < r < 4, and 0 < theta < 2pi
are my bounds set up correct?
I know how to set up the the integral to find the volume inside the sphere but I am not quite sure how to also find the outside of the cylinder. Can someone confirm if this right or wrong?
x^2 + y^2 +z^2 = 16
z^2 = 16 - x^2 - y^2
z = sqrt( 16 - r^2 )
since the problem asks for volume of the sphere z = 2*sqrt( 16 - r^2 )
x^2 + y^2 = 4
r^2 = 4
r = 2
so 2 < r < 4, and 0 < theta < 2pi
are my bounds set up correct?