Dynamics Question: Find Maximum Angular Velocity & Reaction at Pivot

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The discussion centers on a physics problem involving a slender rod pivoted at a point off its center. The goal is to determine the optimal distance from the pivot to the center that maximizes angular velocity as the rod swings to a vertical position. Participants emphasize the importance of conservation of energy, suggesting that both potential energy (PE) and kinetic energy (KE) must be considered in the calculations. The conversation includes hints about using rotational kinetic energy equations and the need to express energy conservation properly. The focus remains on deriving the necessary equations to solve for the distance and corresponding angular velocity.
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1. The problem statement

Hey everyone, I'm a new member here... I'd be grateful if you attempt to solve my following question:

A slender rod of length l is pivoted about a point C located at a distance b from its center G. It's released from rest in a horizontal position and swings freely. Determine (a) the distance b for which the angular velocity of the rod as it passes through a vertical position is maximum, (b) the corresponding values of its angular velocity and of the reaction at C.


Homework Equations



KE = T = 1/2 m V2
PE = V = m g h

The Attempt at a Solution



No idea! :S
 
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I assume that the rod is uniform and that you're just trying to find the optimal pivot point.

Hint: Energy is conserved. How would you express the rotational kinetic energy of the rod?
 
KE = 1/2 I w2?
Do I get the distance b (the distance from point C to the center G of the rod) using PE?
And thank you for the hint...
 
FChebli said:
KE = 1/2 I w2?
Right.
Do I get the distance b (the distance from point C to the center G of the rod) using PE?
You'll have to solve for the distance b using the conditions given. The first step is to write an expression for conservation of energy. (Yes, you'll need PE as well as KE.)
 
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