- #1
leroyjenkens
- 616
- 49
I attached the solution from the solution manual of the integral I'm trying to figure out.
[tex]\int_{-∞}^{∞}x^{2}exp(\frac{-2amx^{2}}{h})[/tex]
The solution of that integral without the x2 in front is [itex]\sqrt{\frac{{\pi}h}{2am}}[/itex]
So with the x2 I assumed I needed to do integration by parts.
So taking u = x2, du = 2xdx
And taking dv to be [itex]exp(\frac{-2amx^{2}}{h})[/itex]
v = [itex]\sqrt{\frac{{\pi}h}{2am}}[/itex]
But v would only equal that in a definite integral. When I'm doing integration by parts, I have an indefinite integral. So I'm kinda stuck here. When I put it into wolfram alpha, I get an error function for the answer to that indefinite integral. Do I put that answer in as v?
Thanks.
[tex]\int_{-∞}^{∞}x^{2}exp(\frac{-2amx^{2}}{h})[/tex]
The solution of that integral without the x2 in front is [itex]\sqrt{\frac{{\pi}h}{2am}}[/itex]
So with the x2 I assumed I needed to do integration by parts.
So taking u = x2, du = 2xdx
And taking dv to be [itex]exp(\frac{-2amx^{2}}{h})[/itex]
v = [itex]\sqrt{\frac{{\pi}h}{2am}}[/itex]
But v would only equal that in a definite integral. When I'm doing integration by parts, I have an indefinite integral. So I'm kinda stuck here. When I put it into wolfram alpha, I get an error function for the answer to that indefinite integral. Do I put that answer in as v?
Thanks.