Efficiency of a heat engine at high temps

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Homework Help Overview

The discussion revolves around the maximum efficiency of a heat engine operating between two temperatures, specifically 550°C and 365°C. The subject area is thermodynamics, particularly focusing on heat engine efficiency calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for efficiency, with one attempting to clarify the correct relationship between the temperatures of the hot and cold reservoirs. There is also a question about the appropriate temperature scale to use in the calculations.

Discussion Status

The discussion is active, with participants exploring the correct expression for efficiency and confirming the use of Kelvin as the temperature scale. Some guidance has been provided regarding the formula, but there is no explicit consensus on the final approach.

Contextual Notes

Participants are working under the assumption that the temperatures must be converted to Kelvin for accurate calculations, and there is an emphasis on understanding the correct application of the efficiency formula.

notsam
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Homework Statement

What is the maximum effciency of a heat engine whose operating tempuratures are 550oC and 365oC?



Homework Equations

E=1-Thot/Tcold



The Attempt at a Solution

PLEASE HELP! My thinking is that the effciency is equal two one minus the temperature in the hot resavour divided by the temperature in the cold resavour. Is that correct?
 
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notsam said:

Homework Statement

What is the maximum effciency of a heat engine whose operating tempuratures are 550oC and 365oC?



Homework Equations

E=1-Thot/Tcold



The Attempt at a Solution

PLEASE HELP! My thinking is that the efficiency is equal to one minus the temperature in the hot reservoir divided by the temperature in the cold reservoir. Is that correct?
You have it upside down. If it was Th/Tc you would have negative efficiency which makes no sense. The correct expression for efficiency of a Carnot engine is:

\eta = 1 - \frac{T_c}{T_h}

AM
 
Ok :) At least I'm somewhat on the right track. THANKS!
 
I use Kelvin correct?
 
notsam said:
I use Kelvin correct?
Correct.

AM
 

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