Electric Circuit Analysis, Nodal Analysis and finding Voltage.

AI Thread Summary
The discussion focuses on the application of Nodal Analysis in two circuits, revealing differing results for voltage V1, with values of 4.8V and 10V respectively. The confusion arises from the presence of a supernode in the second circuit, which the user initially misinterprets. The user realizes their mistake, having confused a voltage source with a current source, leading to the misunderstanding of the circuit analysis. The clarification highlights the importance of accurately identifying circuit components when applying Nodal Analysis. Ultimately, the user resolves their confusion and understands the correct application of the analysis.
Xiao Xiao
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Thread moved from the technical forums, so no Homework Template is shown.
Summary:: The image shows two circuits, in the first one, using Nodal Analysis we find that V1=4.8V, but in the second circuit V1=10 because using KCL - 10+V1=0. I understand what happened in the first circuit, but I don't understand what happened in the second one, they look the same to me except for the existence of a supernode in the second one, which I don't think it should affect it in that way?

Not sure if this is the right forum to post in but this is not HW help since I already know the answer.

IMG_20210409_002055.png

If I apply nodal analysis on the second circuit shouldn't I get a different result for V1?
 
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Which part is confusing you?
 
Joshy said:
Which part is confusing you?
Wait. I actually feel very stupid right now, I got the whole question wrong, I kept seeing the 10V voltage source branch as a current source branch, and got confused, but I got it now.
 
Thread 'Have I solved this structural engineering equation correctly?'

Thread 'Have I solved this structural engineering equation correctly?'

Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
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