two wires in the shape of a 9o degrees circular arc of radius R have charges(adsbygoogle = window.adsbygoogle || []).push({});

+(-) Q distributed uniformly on them. They are positioned opposite eachother in the second and 4th quadrants. Show that the electric feild at the origin is

[tex]\frac{4kQ}{\pi R^2}[/tex]

I tried starting with the electric feild of a line

[tex]\frac{2k\lambda}{r}[/tex]

[tex]\lambda=\frac{Q}{d\theta}[/tex]

plugged that in, and then i wasn't sure what to do... integrate with respect to theta? but then i wasn't sure how to do that when theta was in the denom... help?

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# Electric feild prob

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