Electric Field at Midpoint of Equilateral Triangle

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field at the midpoint between two positive charges (q1 and q2, both +5.0 µC) in an equilateral triangle configuration, with a negative charge (q3, -5.0 µC) at the third vertex. The relevant equation used is E = k * q / r², where k is Coulomb's constant. The user correctly identifies the need to find the distance to the midpoint and considers the components of the electric field, but expresses concern over the magnitude of the result, suggesting a potential miscalculation.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Knowledge of vector components in physics
  • Familiarity with equilateral triangle properties
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the calculation of electric fields from point charges
  • Study vector addition of electric field components
  • Learn about the significance of charge configuration in electric fields
  • Explore the concept of superposition in electrostatics
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric fields in multi-charge systems.

Brit412
Messages
24
Reaction score
0

Homework Statement


The figure shows a system consisting of three charges, q1=+5.0uC, q2=+5.0uC and
q3=-5.0uC, at the vertices of an equilateral triangle (with q2 at the top point of the triangle).
Find the magnitude of the electric field at a point halfway between the charges q1 and q2.
distance= 2.95cm

Homework Equations


i know an equation is E= k q/r^2

The Attempt at a Solution


So since it wanted to know the halfway point, I divided the distance between the points in half and used it as r. And I figured that the charges have an x and y component but what angles do I use??
 
Physics news on Phys.org
Triangle is equilateral. So the sides are equal. Find the distance between the charge q3 and the mid point of charge q1 and q2. The line joining q3 and mid point is perpendicular to the line joining q1 and q2.
 
I got a pretty big number (a number times 10^8). That seems too big??
 

Similar threads

Replies
23
Views
1K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 17 ·
Replies
17
Views
4K