Electric field decelerating electron

AI Thread Summary
An electron is decelerated by a voltage of 1.3V from an initial velocity of 22 Mm/s, leading to a calculated final velocity of 5.2 Mm/s. The work done is derived from the equations W=qU and W=KE_2-KE_1, where the charge is negative due to the electron's charge. There is confusion regarding whether to add or subtract work values, especially when considering the negative charge and the scalar nature of work. The discussion highlights that using a higher voltage, such as 1.3kV, yields more accurate results. Overall, the conversation emphasizes the importance of correctly applying the concepts of work and energy in physics problems.
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Homework Statement


Electron are decelerated by the voltage 1,3V. Initial velocity is 22 Mm/s, what is the final velocity?

Homework Equations


W=qU, W=KE_2-KE_1

The Attempt at a Solution


From above equations I get v_2=sqrt(2(W+KE_1)/m). q is the elementary charge -e so the work is negative in the equation. The answer is 5,2 Mm/s though, I get 21,99 Mm/s so barely any work done. It feels simplified, that the voltage could be used like that.
 
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1.3kV works better. :smile:
 
NascentOxygen said:
1.3kV works better. :smile:
Aarghh, this book has so many errors... Thanks. :) While we're at it, our equation for work is charge*voltage, so here the voltage would be positive and the charge negative. Is that how you do it? I'm often confused whether work should be subtracted or added but have negative value. With vectors, when you solve the corresponding scalar equation the magnitude should come out positive, for example with forces even though a force is in the negative direction according to your diagram. But with work you should get a negative value if it is negative, since it is a scalar. Have I understood correctly?
 
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