Electric Field Direction at Origin: Cancel or Enhance on x-axis?

AI Thread Summary
The discussion centers on determining the direction of the electric field at the origin due to three equal positive charges positioned equidistantly. It is established that the electric field vectors from the charges on the x-axis cancel each other out, while the charge on the y-axis contributes to the field direction. The correct answer to the multiple-choice question is that the electric field at the origin points along the negative y-axis. Participants emphasize the importance of vector addition and expressing the vectors in rectangular coordinates. The final conclusion is that the electric field direction is along -y.
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Homework Statement



three equal and positive charges q are located equidistant from the origin as shown http://s966.photobucket.com/albums/ae146/acherentia/?action=view&current=directionofanelectricfield.jpg . Is the direction of the electric field at the origin a) along x, b)along -x, c) along +y d) along -y

Homework Equations



The electric field is directed outward away from Q when Q is positive.

The Attempt at a Solution



Do the field lines along the x-axis emerging from the charges on the x-axis cancel or enhance each other at the origin?

Do I have to do vector addition on the x-axis to solve this problem?
 
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acherentia said:

Homework Statement



three equal and positive charges q are located equidistant from the origin as shown http://s966.photobucket.com/albums/ae146/acherentia/?action=view&current=directionofanelectricfield.jpg . Is the direction of the electric field at the origin a) along x, b)along -x, c) along +y d) along -y

Homework Equations



The electric field is directed outward away from Q when Q is positive.

The Attempt at a Solution



Do the field lines along the x-axis emerging from the charges on the x-axis cancel or enhance each other at the origin?

Do I have to do vector addition on the x-axis to solve this problem?

Just do the vector addition at the origin. What are the 3 E-field vectors at the origin? (magnitudes and directions)
 
for the charge on the -x axis : kQ/r^3 x ri
for the charge on the +x axis: kQ/r^3 x r-i
for the charge on the +y axis: kQ/r^3 x r-j

so the charges that are sitting on the x-axis will cancel out. how do i write that in a more mathematical way?
 
acherentia said:
for the charge on the -x axis : kQ/r^3 x ri
for the charge on the +x axis: kQ/r^3 x r-i
for the charge on the +y axis: kQ/r^3 x r-j

so the charges that are sitting on the x-axis will cancel out. how do i write that in a more mathematical way?

Correct. In general, you would write the vector sum in rectangular coordinates. Express each individual vector as the sum of its x and y components (using the i,j vector notation, or x-hat, y-hat, etc.), and show the sum of them as a sum of x components and y components, still in rectangular vector notation.

And in this problem, it's just multiple choice anyway. Which is your answer?
 
The answer is d, along -y
 
acherentia said:
The answer is d, along -y

Yep. Good work.
 
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