Electric field due to a finite line of charge

AI Thread Summary
The discussion focuses on calculating the electric field at a point on the x-axis due to a finite line of charge centered on the y-axis. The relevant equations include E=kdQ/r^2 and dQ=Qdy/2a, leading to the expression for the electric field. A specific integral, dE_x= kQxdy/2a(x^2+y^2)^(3/2), is highlighted as challenging, particularly the integration of dy/(x^2+y^2)^(1/2). The solution involves using the substitution y = x tanθ to simplify the integral. This method ultimately confirms the correct answer for the electric field calculation.
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Homework Statement


A line of length 2a on the y-axis centred in the middle of the x-axis with its ends at a and -a on the y axis, has been charged with charge Q. Work out the electric field at point x on the x axis.


Homework Equations


E=kdQ/r^2
dQ=Qdy/2a


The Attempt at a Solution


I have the answer in front of me: Qk*1/(x(x^2+a^2)^1/2)

I start with dE_x= kQxdy/2a(x^2+y^2)^3/2 (added the x component with x/(x^2+y^2)^1/2)
This integral is the bit I don't understand!

How do you integrate dy/(x^2+y^2)^1/2 ?
Apparently the answer is y/(x^2(x^2+y^2)^1/2). How does this work?

And it does give the correct answer if you follow it on. But How do you integrate that?


 
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To do this integral, use the substitution y = x tanθ and see what you get.
 
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