Electric field given electric potential

AI Thread Summary
To find the electric field from the given electric potential V = (210 x² - 170 y²) V, the negative gradient of the potential must be calculated. The electric field is a vector quantity represented as E = -∇V, where ∇ is the gradient operator. The partial derivatives with respect to x and y need to be computed to determine the components of the electric field. The solution involves evaluating the derivatives at the specific point (1.00 m, 3.00 m). Understanding the relationship between electric potential and electric field is crucial for solving such problems.
743344
Messages
19
Reaction score
0
[SOLVED] electric field given electric potential

Homework Statement



The electric potential in a region of space is V = ( 210 x^{2} - 170 y^{2} ) V, where x and y are in meters.

What is the strength of the electric field at ( 1.00 m, 3.00 m ) ?

Homework Equations



E = -dV/ds


The Attempt at a Solution



1. i know i have to find the derivative of the that given equation but i can't figure out where to start...because there are two different variable given...and i don't know in term of which variable i have to find the derivative
 
Physics news on Phys.org
The E-field is a vector quantity and is given by the negative gradient of the potential.

\mathbf{E} = -\nabla V

the \nabla operator is:

\nabla = \frac{\partial}{\partial x} \mathbf{\hat{i}} + \frac{\partial}{\partial y} \mathbf{\hat{j}} +\frac{\partial}{\partial z} \mathbf{\hat{k}}
 
Last edited:
thank you
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top