Electric field given electric potential

AI Thread Summary
To find the electric field from the given electric potential V = (210 x² - 170 y²) V, the negative gradient of the potential must be calculated. The electric field is a vector quantity represented as E = -∇V, where ∇ is the gradient operator. The partial derivatives with respect to x and y need to be computed to determine the components of the electric field. The solution involves evaluating the derivatives at the specific point (1.00 m, 3.00 m). Understanding the relationship between electric potential and electric field is crucial for solving such problems.
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[SOLVED] electric field given electric potential

Homework Statement



The electric potential in a region of space is V = ( 210 x^{2} - 170 y^{2} ) V, where x and y are in meters.

What is the strength of the electric field at ( 1.00 m, 3.00 m ) ?

Homework Equations



E = -dV/ds


The Attempt at a Solution



1. i know i have to find the derivative of the that given equation but i can't figure out where to start...because there are two different variable given...and i don't know in term of which variable i have to find the derivative
 
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The E-field is a vector quantity and is given by the negative gradient of the potential.

\mathbf{E} = -\nabla V

the \nabla operator is:

\nabla = \frac{\partial}{\partial x} \mathbf{\hat{i}} + \frac{\partial}{\partial y} \mathbf{\hat{j}} +\frac{\partial}{\partial z} \mathbf{\hat{k}}
 
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thank you
 
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