Electric field magnitude between two charged disks problem

AI Thread Summary
The discussion centers on calculating the electric field magnitude at the point x = a/2 between two charged disks, one positively charged and the other negatively charged. The initial equation for the electric field along the x-axis of a disk is provided, but the user mistakenly attempts to double it without considering the direction of the fields. A hint suggests substituting a/2 into a general formula for the electric field between the disks, which the user is unsure how to apply. Clarification is sought on what the variable x represents in the formulas. Understanding how to properly substitute and apply the equations is essential for solving the problem accurately.
Brystephor
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Homework Statement


Consider two thin disks, of negligible thickness, of radius R oriented perpendicular to the x axis such that the x axis runs through the center of each disk. (Figure 1) The disk centered at x=0 has positive charge density η, and the disk centered at x=a has negative charge density −η, where the charge density is charge per unit area.
What is the magnitude E of the electric field at the point on the x axis with x coordinate a/2?

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Homework Equations


We will need the equation for the electric field along the x-axis of a disk. I believe it is this:
\frac η {2∈_0} * \left( 1 - \frac x {\sqrt {(x^2+R^2)} } \right)

I'm not sure that we will need anything else since we will be solving symbolically.

The Attempt at a Solution


We will need to find the electric fields emitted from both disks, and then add them, correct? So it seems like we should be able to just double the equation up top since the electric fields will be equivalent but in different directions, resulting in:
\frac η {∈_0} * \left( 1 - \frac x {\sqrt {(x^2+R^2)} } \right)

However, this is incorrect. I am not sure what else to do. MasteringPhysics hint gave me a 'general form' equation of the electric field between the disks that is:

\frac η {2∈_0} * \left( 2 - \frac 1 { \sqrt {1+R^2/(x-a)^2} } - \frac 1 {\sqrt {1+R^2/x^2} } \right)

I can see that the R^2 / x^2 = \arctanθ but I do not understand where the \left( x - a^2 \right) comes from or how to continue from here. Thank you.
 

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Hello brystephor, :welcome:

did you try to substitute your a/2 in the general formula ? surprise !
 
BvU said:
Hello brystephor, :welcome:

did you try to substitute your a/2 in the general formula ? surprise !

I did not do this. I am not sure where to substitute it in for or why I would do such a thing. Clearly a/2 is the point between two disks, but I do not know which of the variables in my general equation I would replace with a/2 or the formula that Mastering Physics gave me.
 
Brystephor said:
I did not do this. I am not sure where to substitute it in for or why I would do such a thing. Clearly a/2 is the point between two disks, but I do not know which of the variables in my general equation I would replace with a/2 or the formula that Mastering Physics gave me.
What does ##x## represent in the formulas you have written?
 
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