Electric field magnitude midway between 2 charges

AI Thread Summary
To find the electric field magnitude midway between two charges, Q1 = 1 C and Q2 = 11 C, separated by 2 m, the formula E = k(Q/r^2) is applied. The calculations initially yield electric field strengths of 9E9 N/C from Q1 and 1.8E10 N/C from Q2. However, the fields produced by the two charges must be considered in terms of their direction, as they will oppose each other. The correct approach involves calculating the net electric field by subtracting the weaker field from the stronger one, rather than simply adding the magnitudes. The final answer requires proper vector consideration to determine the accurate electric field magnitude.
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Homework Statement



What is the electric field magnitude midway between charges of Q1 = 1 C and Q2 = 11 C separated by 2 m?

Homework Equations


E= k (Q/r^2).



The Attempt at a Solution


9E9 x 1C / 1^2 = 9E9 N/C
9E9 x 2C / 1^2= 1.8E10 N/C.

What do I do from here? Any help would be much appreciated thanks!
 
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Would the answer be to add my two final values? I would have 2.7E10 N/C as my final answer... Does this look right?
 
That answer above proves to be not correct. What needs to be changed?!
 

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