Electric Field of a Charged Spherical shell

AI Thread Summary
The discussion revolves around calculating the electric field at specific radii from a charged spherical configuration consisting of a solid conducting sphere and a concentric conducting spherical shell. The solid sphere has a charge of 6.70 µC, while the shell carries a charge of -3.50 µC. The participant initially miscalculated the enclosed charge, assuming it to be the difference between the two charges, which led to incorrect results. Clarification was provided regarding the application of Gauss's Law to determine the correct enclosed charge for the electric field calculations. The participant expressed gratitude upon understanding the correct approach to the problem.
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Homework Statement



A solid conducting sphere of radius 2.00 cm has a charge 6.70 µC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge -3.50 µC. Find the electric field at the folowing radii from the center of this charge configuration.

a) r = 3 cm
b) r = 7 cm

Homework Equations



E = Q(inside) / (4 * pie * Eo * r^2)

Eo = 8.85 * 10^ -12

The Attempt at a Solution



Q(inside) is just 6.7 uc - 3.5 uc = 3.2 uc

I just plug in r to the equation to solve for E

It's wrong, please give me some hints. Thank You
 
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that Q inside you calculated...

would you that value of Q in both questions??


remember enclosed charge
 
Gauss's Law: \int_\text{closed surface} \vec E. d\vec S = q_\text{enclosed}/\epsilon_0
 
Ohh I understand it now, thank you very much
 

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