Electric Field Outside a Solenoid

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SUMMARY

The discussion focuses on calculating the electric field outside a solenoid with a radius of 1.85 cm and 1110 turns per meter, where the current varies as I = 2.50t. The formula used for the electric field is E = (μ0n/2)(di/dt)(R2/r) for r > R, with μ0 = 4π x 10-7 T·m/A. The user initially calculated the electric field to be 1.09 x 10-4 V/m but later identified an error in their calculations.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically solenoids
  • Familiarity with the formula for electric fields around solenoids
  • Knowledge of unit conversions in physics
  • Basic calculus for understanding current variation over time
NEXT STEPS
  • Review the derivation of the electric field formula for solenoids
  • Study the concept of time-varying currents in electromagnetic fields
  • Learn about the implications of Ampère's Law in solenoid applications
  • Explore practical applications of solenoids in electrical engineering
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Students studying electromagnetism, physics educators, and electrical engineers interested in solenoid applications and electric field calculations.

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Homework Statement



A solenoid has a radius of 1.85 cm and 1110 turns per meter. Over a certain time interval the current varies with time according to the expression I = 2.50t, where I is in amperes and t is in seconds. Calculate the electric field 5.47 cm from the axis of the solenoid.


Homework Equations



E = (μ[itex]_{0}[/itex]n/2)(di/dt)(R[itex]^{2}[/itex]/r), r>R

Where μ[itex]_{0}[/itex] = 4∏x10[itex]^{-7}[/itex], n = 1110 turns/meter, di/dt = 2.50, R = 0.0185m, r=0.0547m

The Attempt at a Solution



After plugging in all the numbers and putting things in the right units, I got 1.09x10[itex]^{-4}[/itex] V/m, but this is incorrect. If someone could tell me where I went wrong, I would really appreciate it! Thanks
 
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Nevermind, I found my mistake!
 

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