Electric field strenght of a loop given maximum flux

AI Thread Summary
To find the electric field strength of a circular loop with a diameter of 29 cm and a maximum flux of 7.2e5 Nm^2/C, the formula used is flux = EA. The area of the loop is calculated using the radius, which is half the diameter, leading to the equation E = flux/area. The initial calculation yielded an electric field strength of approximately 34,244,946 N/C, but this was identified as incorrect. Clarification confirmed that the area of the loop is indeed calculated as that of a circle, which is πr^2.
fenixbtc
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Homework Statement


a 29 cm diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. the flux is measured to be 7.2e5 Nm^2/C
what is the electric field strength in units N/C?


Homework Equations


flux = EA


The Attempt at a Solution


7.2e5 Nm^2/C = E * (.29m/2)^2
E = 34244946.4923

apparently it's not the right answer though...

thanks!
David
 
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What is the area of the circle?
 
the area of a circle is pi*r^2...but this is a loop...or are they the same thing?
 
fenixbtc said:
the area of a circle is pi*r^2...but this is a loop...or are they the same thing?
Circular loop and circle is the same.
 
awesome! thank you.
 

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