Electric field strength from x=-a to x = a

AI Thread Summary
The discussion centers on the confusion regarding electric field strength at the point x = 0 between two opposite charges. It is initially believed that the electric field should be zero at this point due to the equal and opposite vectors. However, it is clarified that the electric fields from the charges actually point in the same direction toward the negative charge, resulting in a maximum electric field strength at x = 0. The conversation highlights the importance of careful analysis in physics problems, regardless of their perceived simplicity. Understanding vector directions is crucial in determining the resultant electric field strength.
physiccool78
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Homework Statement


I attached a file.

Numbers 10 and 12.

Homework Equations



kQq/r, kQq/r^2

The Attempt at a Solution



I am confused about this problem. Shouldn't the electric field strength be 0 when x = 0? The charges are opposite and adding two opposite vectors with equal magnitude should be 0 right? So how come the answer says that the electric field strength is the greatest at x = 0 then? Thank you.
 

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They are in opposite positions on the y axis,so the vectors of the electric fields point in the same direction.They both point to the negative charge.
 
Wow... Thank you and now I feel embarrassed for asking this question! I can't believe I overlooked this. Thank you.
 
Just be a little more patient with physics problems,however simple or confusing they might be.
 

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