Calculating Electric Field Ratios for H+ and K+ Ions

In summary, the ratio of electric fields, E1/E2, for H+ and K+ ions can be calculated by using the formula qR^2/Qr^2. There is no hidden trick to this problem, it is a straightforward plug and chug computation. However, in actuality, the computation of electric fields is more complex than this simplified formula.
  • #1
nemzy
125
0
The ratio of electric fields, E1/E2, at the surfaces of ions when H+ is the first ion (q=+1 and R=0.00001 Angstrom) and K+ is the second ion (Q=+1 and R=1.33 Angstrom) is:

how would u solve this kind of problem?

well i know that the ratio of E1/E2 is qR^2/Qr^2

so do i just plug in those numbers and compute?

if that's the case, is this problem this easy or is their some kinda tricky hidden thing that I am overlooking?
 
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  • #2
No trick. Easy problem. Plug 'n' chug.

In reality, the computation of the electric field is far more complex than just using the formula given...but since that's what you're given at this level, that's what you kmust use.
 
  • #3


To solve this problem, you would first need to understand the concept of electric fields and how they are calculated. Electric fields are a measure of the force experienced by a charged particle in an electric field. In this case, we are looking at the electric field at the surface of two ions, H+ and K+.

The formula for calculating electric field is E = kq/r^2, where k is the Coulomb's constant, q is the charge of the ion, and r is the distance from the ion. In this problem, we are given the values for q and r for both ions.

To find the ratio of electric fields, we can use the formula E1/E2 = (q1/r1^2)/(q2/r2^2). Plugging in the values for H+ and K+ ions, we get:

E1/E2 = (1/0.00000000001^2)/(1/1.33^2) = 1.33^2/0.00000000001^2 = 1.77 x 10^22

So, the ratio of electric fields at the surfaces of H+ and K+ ions is 1.77 x 10^22. This means that the electric field at the surface of K+ ion is 1.77 x 10^22 times stronger than the electric field at the surface of H+ ion.

This problem may seem straightforward, but it is important to understand the concept of electric fields and how they are calculated. It is also important to double-check your calculations and make sure you are using the correct units. Overall, this is a relatively simple problem, but it is always a good idea to carefully read and understand the question before attempting to solve it.
 

1. What is the formula for calculating electric field ratios for H+ and K+ ions?

The formula for calculating the electric field ratio for H+ and K+ ions is given by E(H+)/E(K+) = q(H+)/q(K+), where E represents the electric field and q represents the charge of the ions.

2. How do you determine the charge of H+ and K+ ions?

The charge of an ion can be determined by its atomic number and the number of electrons it has. In the case of H+ and K+ ions, H+ has a charge of +1 and K+ has a charge of +1 as well.

3. What is the significance of calculating electric field ratios for H+ and K+ ions?

Calculating electric field ratios for H+ and K+ ions helps in understanding the strength of the electric field between these two ions. This information is useful in various fields of science, such as chemistry, physics, and biology.

4. Can the electric field ratios for H+ and K+ ions be negative?

Yes, the electric field ratios for H+ and K+ ions can be negative. This indicates that the direction of the electric field is opposite for these two ions.

5. How can the electric field ratios for H+ and K+ ions be used in practical applications?

The electric field ratios for H+ and K+ ions can be used in various practical applications, such as studying the behavior of ions in an electrolytic cell, determining the strength of an acid or base solution, and understanding the movement of ions in a magnetic field.

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