Electric Fields components help

Click For Summary
SUMMARY

The discussion centers on calculating the electric field components generated by two identical positive point charges, each with a magnitude of 9.00 nC, positioned symmetrically at x = 0.250 m and x = -0.250 m. At the origin, the electric field components are E_x = 0 and E_y = 0 due to symmetry, resulting in a net electric field of zero. For the point at x = 0.500 m, the participant correctly identifies that E_y = 0 and begins calculating E_x, but needs to consider contributions from both charges to find the total electric field.

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with Coulomb's Law
  • Knowledge of vector addition in physics
  • Basic trigonometry for calculating angles
NEXT STEPS
  • Review Coulomb's Law for electric field calculations
  • Learn about vector addition of electric fields
  • Study the concept of electric field lines and their properties
  • Explore the effects of multiple charges on electric fields
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, as well as educators looking for practical examples of electric field calculations involving point charges.

lilangel50us
Messages
2
Reaction score
0
In a rectangular coordinate system, a positive point charge q = 9.00 nC is placed at the point x= 0.250 m, y = 0, and an identical point charge is placed at x= -0.250 m, y = 0. Find the x and y components and the magnitude and direction of the electric field at the following points.

(a) Find the x and y components and the magnitude of the electric field at the origin.

Since the two point charges are from equal distances from the origin, I got that as E_x =0, E_y=0, and E_net = 0.

(b) Find the x and y components and the magnitude and direction of the electric field at x= 0.500 m, y=0

I figured out that the angle of this would be 0 degrees from the positive x axis.
 
Physics news on Phys.org
I realized I never finished typing out everything.

(a) I found that out conceptually. Since the two charges are positive, their electric fields will repel, and since they are equidistant from the origin, the origin will have no electric field.

(b) I'm not really sure what to do here.

I figure that E_y = 0. To calculate E_x, I think I would have to do the following:

E_x = (k(9.00 nC)/(.25)^2)/9.00nC = E_net

Am I doing it properly?
 
(a) looks ok by symmetry.

(b) You have to add up the E_x contributions for both charges. The one you wrote is for the charge at x=0.25 What about the one at x=-0.25?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K