Electric fields, distance, and potential difference

AI Thread Summary
The discussion revolves around calculating the electric field between the plates of a TV set, given a potential difference of 20 kV and a distance of 1.0 cm. The correct formula to use is E = V/D, where E is the electric field, V is the potential difference, and D is the distance. A participant initially miscalculated the conversion of units but later confirmed their final answer as 2.0 x 10^6 N/C. The group consensus is that the calculations appear correct, but there is confusion about the expected answer.
goWlfpack
Messages
51
Reaction score
0

Homework Statement



The potential difference between the accelerating plates of a TV set is about 20 kV. If the distance between the plates is 1.0 cm, find the magnitude of the uniform electric field in the region between the plates.



Homework Equations



V=ED so E=V/D where E is the electric field and D is the distance between the plates



The Attempt at a Solution



I am soooo confused. I swear I am just plugging in the numbers. since kv is 1000 v and cm is 1/100th of a m i did 20,000/.01 and that was wrong. I did this because they want the answer in N/C and i thought that conversion factor was right... any suggestions?
 
Physics news on Phys.org
Your equation looks right to me. What did you get for a final answer? Did you include the units in your answer?
 
yes the units are already written after the equation. I got 2.0*10^6. after going over everything it looks right to me...
 
Yes, looks right to me too. Weird.
 
What's the answer supposed to be?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Two different dielectrics between parallel-plate capacitor
Replies
6
Views
2K
Potential difference between two points in an electric field
Replies
1
Views
2K
Find the electric field between 2 finite discs
Replies
16
Views
1K
Charge on a grounded conducting sphere in a uniform electric field, after ungrounding and movement
Replies
1
Views
1K
Calculating eletric potential using line integral of electric field
Replies
1
Views
2K
Confused about direction of electric field
Replies
7
Views
3K
Polarities of capacitor plates in a complex circuit
Replies
14
Views
2K
Capacitors, equipotentials, and electric fields
Replies
5
Views
890
Earthing of two parallel conducting plates
Replies
11
Views
1K
Electric field between two parallel plates
2
Replies
58
Views
5K

Hot Threads

Recent Insights

Back
Top