Electric Flux through the semisphere

AI Thread Summary
The electric flux through a semisphere aligned with an electric field parallel to the X-axis can be calculated using the formula φ = ∫ E·dA. This flux is equivalent to the flux through the projection of the semisphere onto the YZ plane, which is perpendicular to the X-axis. When considering a sphere centered at the origin with no charge inside, the electric flux is zero, similar to the case with a cube. However, if there is a charge within the sphere, the flux would be determined by the equation φ = Q/ε₀. The discussion emphasizes the relationship between electric fields, flux, and charge presence.
YoungILoveYou
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Hello, if we have an electric field E parallel to X axis and a semisphere with axis parallel to X axis, which is the electric flux through the semisphere?
 
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YoungILoveYou said:
Hello, if we have an electric field E parallel to X axis and a semisphere with axis parallel to X axis, which is the electric flux through the semisphere?
The flux is:

\phi = \int E\cdot dA

Since flux is a dot product of the field and area, the flux through the semisphere is the same as the flux through the projection of the semisphere onto the yz plane (which is perpendicular to x axis).

AM
 
Ok, Thanks for the answer.
Another thing.
If there is a sphere centered at the origin, with radius R, the Flux is zero?
I think that is similar to cube example!

http://img153.imageshack.us/my.php?image=cubeqq7.jpg

What do you think?

Bye
 
Yes, if there's no charge inside it, which there wouldn't be with that field, I think. If there is a charge inside the sphere, the flux is Q/epsilon0.
 
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