What is the magnitude of the force of repulsion between them?

AI Thread Summary
The discussion focuses on calculating the force of repulsion between two point charges when their separation is reduced to 0.293 times the original distance. The relevant formula for the force is F = k * (q1 * q2) / r^2, where k is Coulomb's constant. By substituting 0.293 * r into the formula, the new force can be calculated. The final result for the force of repulsion is approximately 2.68 x 10^-27 N. Understanding the relationship between distance and force is crucial in electrostatics.
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Homework Statement



Two point charges are separated by a distance r and repel each other with a force F. If
their separation is reduced to 0.293 times the original value, what is the magnitude of
the force of repulsion between them?

Homework Equations





The Attempt at a Solution

 
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What would your approach be here?
 
0.293 + r+F= r+ 0.293?
 
Based on what formula?
 
F= Keq/r sqed
 
So F = k*qq/r2

They want you to use .293*r instead or r

What effect does that have on F?
 
F is consider the electric field force
 
Yes.

So what's the answer?
 
F = k*qq/r2 F= 8.99x 10^9 * (1.6x 10 ^-19 ) sqed divide by .293 = 2.68x 10^ -27,
 
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